MIL-HDBK 1028/6A
Section 3:
SYSTEM COMPONENT SELECTION
3.1
Standardization of Components.
Standardization of FPUS
components requires that central facilities equipment and main distribution
components be selected for energy-efficient operation and according to the
basic design methods defined in pars. 3.1.1 through 3.1.4.
3.1.1
Minimum Unit Demands. The minimum aircraft unit demands for
aircraft ground support are as detailed in par. 2.2.1.
3.1.2
Maximum Unit Capacities. The maximum unit capacity of
central facilities equipment shall be based upon the number of ground
support equipment (GSE) available to serve as standby. Generally, that
availability will be approximately one-fourth of the central facilities
total demand as determined in Section 2.
3.1.3
Design Methods. The preceding requirements of aircraft unit
demands, diversity of loads, minimum unit demand, and maximum capacities of
central facilities equipment, when properly coordinated, formulate the
design method. The design method is formulated on the basis of the
requirements of carrier-type aircraft. The number of general purpose or
special mission aircraft assigned to a particular facility is
unpredictable. For such applications, determine the total utility demand
by dividing the product of the aircraft unit demand and the number of
aircraft by the diversity factor.
3.1.4
Design Method Summaries. Tables 2 through 7 summarize the
design method for the determination of the quantity and ratings of the
central facilities equipment. Calculations are based on air at standard
conditions of 14.7 psia (101.35 kPa), 68 degrees F (20 degrees C), 36
percent relative humidity.
3.1.4.1
Selecting Starting Air Equipment. Table 2 summarizes the method
for selecting starting air equipment. Table 3 presents an example for a
starting air system based upon the following conditions:
a)
Compressor discharge pressure = 250 psig (1723.5 kPa)
b)
Pressure drop, compressor-to-receiver = 10 psig (68.94 kPa)
c)
Pressure drop, PRV to service point = 20 psig (137.88 kPa)
d) Pipeline volume = 2300 cu. ft. (64.4 cu. m) at an average
pressure of 115 psig (792.81 kPa)
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